Quick Reference
The PHP array_replace() function replaces the values of the first array with the values from following arrays.
- If a key from array1 exists in array2, values from array1 will be replaced by the values from array2; if the key only exists in array1, it will be left as it is
- If a key exist in array2 and not in array1, it will be created in array1
- If multiple arrays are used, values from later arrays will overwrite the previous ones
<?php
$a1 = array('Car 1' => 'Lamborghini', 'Car 2' => 'Ferrari');
$a2 = array('Car 2' => 'Maserati', 'Car 3' => 'Alfa Romeo');
print_r(array_replace($a1, $a2));
?>Note
Arrays count starting from zero NOT one. So item 1 is position [0], item 2 is position [1], and item 3 is position [2] … and so on.
Output
Array ( [Car 1] => Lamborghini [Car 2] => Maserati [Car 3] => Alfa Romeo )Syntax
array_replace(array1, array2, array3, ...)Parameters
| Parameter | Description |
|---|---|
| array1 | Specifies an array (required) |
| array2 | Specifies an array which will replace the values of array1 |
| array3, ... | Specifies additional arrays to replace the values of array1 and array2, etc.; values from later arrays will overwrite the previous ones |
PHP Notes:
- When using PHP, single or double quotation marks are acceptable and work identically to one another; choose whichever you prefer, and stay consistent
- Arrays count starting from zero NOT one; so item 1 is position [0], item 2 is position [1], and item 3 is position [2] … and so on
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